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Showing posts with label Tech Mahindra Sample Aptitude Questions. Show all posts
Showing posts with label Tech Mahindra Sample Aptitude Questions. Show all posts
Saturday, December 10, 2011
Tuesday, September 6, 2011
Tech Mahindra Sample Aptitude Questions
Below are few sample aptitude questions of the difficulty level that can be expected on Tech Mahindra's placement tests/ interviews.
Placement Question 1
Consider a group of working men. If 1/10th of the workers are absent then work of each person would be increased by.
a. 20% b. 22.22% c. 10% d. 11.11%
Answer 1
Answer is d. 11.11%
Let us assume 100 units of work is divided among 10 men.
When no one is absent, each member have to do 100/10 = 10 units of the work
With 1/10th of men absent, there would be 9 men present.
Now, if 100 units of work is to be done by the 9 men present, each should do 100/9 units of work.
Extra work required from each member when only 9 men are present = 100/9 - 10 = 10/9 units.
Percentage of increase of work for each member = (Extra work required from each member when only 9 men are present)/ (Original amount of work when everyone is present) X 100 % = ((10/9)/10)X 100% = 11.11%
Placement Question 2
Consider the following statements,
All members of team A are good tall guys with an average height of 6 feet.
Average of the height of members of team B is lesser than that of team A.
Which could be true among the below options.
a) Every member of team B is shorter than each member of team A.
b) Few members of team B could be over 6 feet.
Answer 2
Answer is Option b) Few members of team B could be over 6 feet.
Reason : The statement says that there is a possibility that few members of team B can actually be taller than few members of team A.
Placement Question 3
John is supposed to walk from his house to park every morning. One morning, he is in real hurry and wants to save at least 1/3rd of the time. By how much percentage he should increase his speed.
a. 100% b. 33% c. 66% d. 50%
Answer 3
Answer is d. 50%
Let the distance between his house and park be 100 metres.
Lets assume he takes 30 mins daily. Hence his speed would be 100/30.
One day, if he wishes to save 1/3rd of 30 minutes, that is 10 minutes, he should cover the distance in 20 minutes in which case his speed would be 100/20.
Required increment in speed = 100/20 - 100/30
Percentage of increase in speed = (Required increment in speed / Original speed) X 100 % = ((100/20 - 100/30) / 100/30 )X100 % = 50%.
Placement Question 1
Consider a group of working men. If 1/10th of the workers are absent then work of each person would be increased by.
a. 20% b. 22.22% c. 10% d. 11.11%
Answer 1
Answer is d. 11.11%
Let us assume 100 units of work is divided among 10 men.
When no one is absent, each member have to do 100/10 = 10 units of the work
With 1/10th of men absent, there would be 9 men present.
Now, if 100 units of work is to be done by the 9 men present, each should do 100/9 units of work.
Extra work required from each member when only 9 men are present = 100/9 - 10 = 10/9 units.
Percentage of increase of work for each member = (Extra work required from each member when only 9 men are present)/ (Original amount of work when everyone is present) X 100 % = ((10/9)/10)X 100% = 11.11%
Placement Question 2
Consider the following statements,
All members of team A are good tall guys with an average height of 6 feet.
Average of the height of members of team B is lesser than that of team A.
Which could be true among the below options.
a) Every member of team B is shorter than each member of team A.
b) Few members of team B could be over 6 feet.
Answer 2
Answer is Option b) Few members of team B could be over 6 feet.
Reason : The statement says that there is a possibility that few members of team B can actually be taller than few members of team A.
Placement Question 3
John is supposed to walk from his house to park every morning. One morning, he is in real hurry and wants to save at least 1/3rd of the time. By how much percentage he should increase his speed.
a. 100% b. 33% c. 66% d. 50%
Answer 3
Answer is d. 50%
Let the distance between his house and park be 100 metres.
Lets assume he takes 30 mins daily. Hence his speed would be 100/30.
One day, if he wishes to save 1/3rd of 30 minutes, that is 10 minutes, he should cover the distance in 20 minutes in which case his speed would be 100/20.
Required increment in speed = 100/20 - 100/30
Percentage of increase in speed = (Required increment in speed / Original speed) X 100 % = ((100/20 - 100/30) / 100/30 )X100 % = 50%.